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korrekt calculation of amphours.

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better output with more info
This commit is contained in:
lukas-heiligenbrunner 2020-04-11 19:39:26 +02:00
parent 882b793cd2
commit 33236b4a11
1 changed files with 26 additions and 11 deletions
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37
src/main.cpp
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@ -4,15 +4,18 @@
#include "Arduino.h"
#define MINVOLTAGE 2.5
#define OHM 55
#define OHM 4.7
#define MEASUREPIN A3
#define MOSFETPIN A2
void setup() {
Serial.begin(9600);
pinMode(LED_BUILTIN, OUTPUT);
pinMode(8, OUTPUT);
pinMode(A0, INPUT);
pinMode(MOSFETPIN, OUTPUT);
pinMode(MEASUREPIN, INPUT_PULLUP);
digitalWrite(8, LOW);
digitalWrite(MOSFETPIN, LOW);
}
int i = 0;
@ -20,25 +23,37 @@ double all = 0;
void loop() {
Serial.println();
double voltage = (float) (analogRead(A0)) / 1024 * 5;
if (voltage > MINVOLTAGE) {
digitalWrite(8, HIGH);
double voltage = (float) (analogRead(MEASUREPIN)) / 1024 * 5;
if (voltage > MINVOLTAGE && voltage < 4.5) {
digitalWrite(MOSFETPIN, HIGH);
double current = voltage / OHM;
double watt = current * voltage;
double amphours = watt / 360;
double amphours = current / 360; // every 10secs is a measurement point...
all += amphours;
Serial.print(all * 1000, 5);
Serial.print("mA/h already captured after - ");
Serial.print(i * 10);
Serial.println("s");
Serial.print("Watts: ");
Serial.println(watt);
Serial.print("Current: ");
Serial.println(current);
i++;
} else {
digitalWrite(8, LOW);
} else if (voltage <= MINVOLTAGE) {
digitalWrite(MOSFETPIN, LOW);
Serial.print("FINISHED voltage below minvoltage - ");
Serial.print(all / 1000, 5);
Serial.print(all * 1000, 5);
Serial.print("mA/h in - ");
Serial.print(i * 10);
Serial.println("s");
Serial.println("please restart the print");
delay(999999999);
} else if (voltage > 4.2) {
Serial.println("no battery connected!");
}
Serial.print("Voltage: ");
Serial.println(voltage);
delay(10000);
}